In: Statistics and Probability
The following data are the monthly salaries y and the
grade point averages x for students who obtained a
bachelor's degree in business administration.
| GPA | Monthly Salary ($) | 
| 2.6 | 3,600 | 
| 3.4 | 3,900 | 
| 3.6 | 4,300 | 
| 3.2 | 3,700 | 
| 3.5 | 4,200 | 
| 2.9 | 2,200 | 
The estimated regression equation for these data is = -414.9 + 1,270.3x and MSE =425,236
A) Develop a point estimate of the starting salary for a student with a GPA of 3.0 (to 1 decimal).
B) Develop a 95% confidence interval for the mean starting salary for all students with a 3.0 GPA (to 2 decimals).
C) Develop a 95% prediction interval for Ryan Dailey, a student with a GPA of 3.0 (to 2 decimals).

a)
Point estimate =-414.9+1,270.3*3 =3396.0
b)
| std error of CI=s*√(1/n+(x0-x̅)2/Sxx)= | 306.3634 | |
| for 95 % CI value of t= | 2.776 | |
| margin of error E=t*std error= | 850.601 | |
| lower confidence bound=xo-E= | 2545.40 | |
| Upper confidence bound=xo+E= | 4246.60 | |
95% confidence interval for the mean starting salary =(2545.40 ; 4246.60)
c)
| std error of PI=s*√(1+1/n+(x0-x̅)2/Sxx)= | 720.4825 | |
| for 95 % CI value of t= | 2.776 | |
| margin of error E=t*std error= | 2000.380 | |
| lower confidence bound=xo-E= | 1395.62 | |
| Upper confidence bound=xo+E= | 5396.38 | |
95% prediction interval for Ryan Dailey =(1395.62 , 5396.38)