Question

Use the weights of cans of generic soda as sample​ one, and use the weights of cans of the diet version of that soda as sample two. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Construct a 99​% confidence interval estimate of the difference between the mean weight of the cans of generic soda and the mean weight of cans of the diet version of that soda. Does there appear to be a difference between the mean​ weights?

Weight of Generic SodaWeight of Generic Soda	Weight of Diet SodaWeight of Diet Soda
0.8071	0.8643
0.8402	0.8542
0.8564	0.8342
0.8751	0.8173
0.8677	0.8224
0.8843	0.8091
0.8833	0.8039
0.8902	0.8193
0.8986	0.8126
0.8136	0.8611
0.8105	0.8638
0.8103	0.8672
0.8375	0.8526
0.8331	0.8511
0.8283	0.8531
0.8303	0.8722
0.8255	0.8532
0.8325	0.8698
0.8435	0.8536
0.8467	0.8169
0.8431	0.8493
0.8891	0.8122
0.8755	0.8136
0.8711	0.8355
0.8415	0.8313
0.8565	0.8118
0.8833	0.8285
0.8944	0.8336
0.8707	0.8376
0.8541	0.8422
0.8581	0.8096
0.8589	0.8055
0.8604	0.8125
0.8727	0.8156
0.8712	0.8214
0.8702	0.8087

Assume that population 1 is the generic soda and population 2 is the diet soda.

The 99​% confidence interval is ____  ounces < μ1- μ2 < _____ ounces.
​(Round to four decimal places as​ needed.)

Answer 1

I have used Minitab software

Steps

1. Enter the data in minitab
2. Stat-Basic Statistics-2 sample t
3.   
4. Option
5. 
6. ok-ok

output

HenceThe 99​% confidence interval is _0.0065___  ounces < μ1- μ2 < __ 0.0360___ ounces.​

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