Q2. An enzyme has a Km of 2.8 * 10-5 M and a Vmax of 53...

Q2. An enzyme has a K_m of 2.8 * 10^-5 M and a V_max of 53 μM/s.

(i) Calculate V_o if [S] = 3.7 * 10^-4 M and [I] = 4.8 *10^-4 M for (a) a competitive inhibitor, (b) a noncompetitive inhibitor and (c) an uncompetitive inhibitor. (Assume K_i = 1.7 * 10^-5 M.)

(ii) The degree of inhibition is given by i (%) = 100(1 - V_i/V_o). Calculate the percent inhibition in each of the three cases above.

Expert Solution

queen_honey_blossom answered 2 years ago

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