In: Chemistry
Suppose you have an enzyme that has a KM value of 10uM for its substrate and a Vmax= 7umol-mg-1min-1. In the presence of a reversible inhibitor, the KM value increases to 40uM and the Vmax remains the same. What type of inhibitor is this and what is the KI value of this inhibitor?
Ans. Given,
Km increase from 10 µM to 40 µM.
Vmax remains constant
Reversible inhibition is the characteristic of competitive inhibitor that simultaneously increase KM but leaves Vmax unaffected.
#2. Apparent Km = Km {1 + ([I] / KI)}
Or, Km,app = Km {1 + ([I] / KI)}
Where,
Km,app = 40 µM
Km = 10 µM
[I] = ?
KI = ? to be calculated.
Concentration of inhibitor [I] that leads to increase in Km must be known to get the value of KI.
Put the value of [I] (if you were provided, say in some part of this question) in above reaction to calculate KI.