In: Electrical Engineering
A seven segment display is a arrangement of LED in H shape The truth table of a seven segment led is created with combination of inputs for each decimal number and is shown below
input |
output |
||||||||||
Decimal number |
A |
B |
C |
D |
a |
b |
c |
d |
e |
f |
g |
0 |
0 |
0 |
0 |
0 |
x |
x |
x |
x |
x |
x |
|
1 |
0 |
0 |
0 |
1 |
x |
x |
|||||
2 |
0 |
0 |
1 |
0 |
x |
x |
x |
x |
x |
||
3 |
0 |
0 |
1 |
1 |
x |
x |
x |
x |
x |
||
4 |
0 |
1 |
0 |
0 |
x |
x |
x |
x |
|||
5 |
0 |
1 |
0 |
1 |
x |
x |
x |
x |
x |
||
6 |
0 |
1 |
1 |
0 |
x |
x |
x |
x |
x |
x |
|
7 |
0 |
1 |
1 |
1 |
x |
x |
x |
||||
8 |
1 |
0 |
0 |
0 |
x |
x |
x |
x |
x |
x |
x |
9 |
1 |
0 |
0 |
1 |
x |
x |
x |
x |
x |
Now we find the Boolean expression for each of output function
a=f(A,B,C,D)=m(0,2,3,5,7,8,9)
b=f(A,B,C,D)=m(0,1,2,3,4,7,8,9)
c=f(A,B,C,D)=m(0,1,3,4,5,6,7,8,9)
d=f(A,B,C,D)=m(0,2,3,5,6,8)
e=f(A,B,C,D)=m(0,2,6 8)
f=f(A,B,C,D)=m(0,4,5,6,8,9)
g=f(A,B,C,D)=m(2,3,4,5,6,8,9)
next we draw the K map for each of output and simplify it
Next we draw the circuit using logic gates where A<B<C<D is input and output are a,b,c, d,e,f,g,