In: Electrical Engineering
A seven segment display is a arrangement of LED in H shape The truth table of a seven segment led is created with combination of inputs for each decimal number and is shown below
| 
 input  | 
 output  | 
||||||||||
| 
 Decimal number  | 
 A  | 
 B  | 
 C  | 
 D  | 
 a  | 
 b  | 
 c  | 
 d  | 
 e  | 
 f  | 
 g  | 
| 
 0  | 
 0  | 
 0  | 
 0  | 
 0  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
|
| 
 1  | 
 0  | 
 0  | 
 0  | 
 1  | 
 x  | 
 x  | 
|||||
| 
 2  | 
 0  | 
 0  | 
 1  | 
 0  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
||
| 
 3  | 
 0  | 
 0  | 
 1  | 
 1  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
||
| 
 4  | 
 0  | 
 1  | 
 0  | 
 0  | 
 x  | 
 x  | 
 x  | 
 x  | 
|||
| 
 5  | 
 0  | 
 1  | 
 0  | 
 1  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
||
| 
 6  | 
 0  | 
 1  | 
 1  | 
 0  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
|
| 
 7  | 
 0  | 
 1  | 
 1  | 
 1  | 
 x  | 
 x  | 
 x  | 
||||
| 
 8  | 
 1  | 
 0  | 
 0  | 
 0  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
| 
 9  | 
 1  | 
 0  | 
 0  | 
 1  | 
 x  | 
 x  | 
 x  | 
 x  | 
 x  | 
||
Now we find the Boolean expression for each of output function
a=f(A,B,C,D)=m(0,2,3,5,7,8,9)
b=f(A,B,C,D)=m(0,1,2,3,4,7,8,9)
c=f(A,B,C,D)=m(0,1,3,4,5,6,7,8,9)
d=f(A,B,C,D)=m(0,2,3,5,6,8)
e=f(A,B,C,D)=m(0,2,6 8)
f=f(A,B,C,D)=m(0,4,5,6,8,9)
g=f(A,B,C,D)=m(2,3,4,5,6,8,9)
next we draw the K map for each of output and simplify it


Next we draw the circuit using logic gates where A<B<C<D is input and output are a,b,c, d,e,f,g,
