In: Computer Science
For the above program, we need to have the following things into consideration.
Following is the python code:
# Printing the post order post_order = [] def postorder(inorder, preorder, n): if preorder[0] in inorder: root = inorder.index(preorder[0]) if root != 0: # left subtree exists postorder(inorder[:root], preorder[1:root + 1], len(inorder[:root])) if root != n - 1: # right subtree exists postorder(inorder[root + 1:], preorder[root + 1:], len(inorder[root + 1:])) post_order.append(preorder[0]) def get_preorder(inorder, preorder): postorder(inorder, preorder, len(inorder)) # Driver Code inorder = [4, 2, 5, 1, 3, 6]; preorder = [1, 2, 4, 5, 3, 6]; n = len(inorder) print("Postorder traversal ") get_preorder(inorder, preorder) print(post_order)
Following is the snippet of the above program .:
The Output of the above program.
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