Question

In: Physics

Two speakers spaced emitting identical sound waves in phase with each other of wavelength 1.00 m...

Two speakers spaced emitting identical sound waves in phase with each other of wavelength 1.00 m are spaceced 5.00 m from eachother. At what minimal distance (in m) from one of them should an observer stand to hear almost nothing (the first minimum)(__________)? The first maximum after this minimum (__________)? Second minimum (__________)? Second maximum (__________)? Third minimum (__________)? Third maximum (__________)? How many minima overall can be observed (__________)? How many maxima (__________)?

Solutions

Expert Solution

given, wavelengh, = 1m

since both sound waves are in phase , so , phase angle, = 0

Let d be the path difference

Condition for mimima , d =/2 + n

condition for máxima, d = m

let observer is standing infront of 1st speaker at distance y from speaker ,

then path difference, d = R2 - R1

d = (y2 + 52)1/2 - y

for first mínima, n=0

(y2 + 52)1/2 - y = 1*1/2

y2 + 25 = (y + 0.5)2

y2 + 25 = y2 + 0.25 + y

só, y = 24.75 m

for first máxima after mínima , m=1

(y2 + 52)1/2 - y = 1*1

y2 + 25 = (y + 1)2

y2 + 25 = y2 + 1 + 2y

só, y = 12 m

for second mínima, n=1

(y2 + 52)1/2 - y = 3/2*1

y2 + 25 = (y + 1.5)2

y2 + 25 = y2 + 2.25 + 3y

só, y = 7.58 m

for second máxima after mínima , m=2

(y2 + 52)1/2 - y = 2*1

y2 + 25 = (y + 2)2

y2 + 25 = y2 + 4 + 4y

só, y = 5.25 m

for third mínima , n=2

(y2 + 52)1/2 - y = 5/2*1

y2 + 25 = (y + 2.5)2

y2 + 25 = y2 + 6.25 + 5y

só, y = 3.75 m

for third máxima after mínima , m=3

(y2 + 52)1/2 - y = 3*1

y2 + 25 = (y + 3)2

y2 + 25 = y2 + 9 + 6y

só, y = 2.67 m

when observer is standing in line with the speakers

d = R2 - R1

= x + 5 - x = 5

5 = 5 * . só fifth máxima when y = 0

s0, total number of maxima Including both side = 4*2 + 1= 9

since at y= 0. we have 5th maxima , so there will be 5th minima too for certain positive y

so, total number of minima = 5 *2 = 10


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