In: Operations Management
a. Optimal order quantity
b. Number of orders per year
c. The supplier is willing to give a discount of 3% on the price of each set if the manager of the store orders 3,000 sets at a time. Should the manager accept the offer?
Please find below answer to first question :
Following are the relevant details :
Annual demand = D = 250 lens pairs every year
Ordering cost = C = $36
Unit inventory carrying cost = I = 20% of $100= $20
Therefore, optimum order quantity which minimizes sum of annual ordering cost and inventory holding cost (EOQ)
= Square root ( 2 x 250 X 36/20)
= 30 PAIRS
Annual ordering cost = C x D/EOQ = $36 x 250/30 = $300
Annual inventory holding cost = I x EOQ / 2 = $20 X 30/2 = $300
Annual cost of lens pairs = $100 x 250 = $25,000
Total cost = $300 + $300 + $25000 = $25600
Different scenario : Order quantity 50lens pairs
Revised cost of lens pairs after 10% discount = 90% of $100 = $90
Annual unit inventory cost = I = 20% of $90 = $18
Annual ordering cost = C X D/ORDER QTY = $36 x 250/50 = $180
Annual inventory holding cost = I x Order qty/ 2 = $18 x 50/2 = $450
Annual cost of lens pairs = $90 x 250 = $22500
Total cost = $180 + $450 +$22500 = $23130
Therefore, lesser total cost is incurred when order quantity is 50 or more.
Best order quantity will be 50or more with total annual cost = $23130