A simple random sample of 81 is selected from a population with a standard deviation of...

A simple random sample of 81 is selected from a population with a standard deviation of 17. The degree of confidence is 90%. What is the margin of error for the mean?

Solutions

Expert Solution

Z score for 90% confidence interval = Z_0.05 = 1.645

Margin of error = Z_0.05 * sd / sqrt(n) = 1.645 * 17 / sqrt(81) = 3.107

orchestra answered 10 months ago

Next > < Previous

Related Solutions

A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and...

A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and unknown mean ?. Calculate a 99 % confidence interval for ? for each of the following situations: (a) n=55, x¯=100.4 ≤?≤ (b) n=75, x¯=100.4 ≤?≤ (c) n=105, x¯=100.4 ≤?≤

A simple random sample of 50 items from a population with a standard deviation of 7,...

A simple random sample of 50 items from a population with a standard deviation of 7, resulted in a sample mean of 38. If required, round your answers to two decimal places. a. Provide a 90% confidence interval for the population mean. b. Provide a 95% confidence interval for the population mean. c. Provide a 99% confidence interval for the population mean.

A random sample of ?n measurements was selected from a population with standard deviation 13.913.9 and...

A random sample of ?n measurements was selected from a population with standard deviation 13.913.9 and unknown mean ?μ. Calculate a 9999 % confidence interval for ?μ for each of the following situations: (a) ?=35, ?⎯⎯⎯=104.9n=35, x¯=104.9 (b) ?=60, ?⎯⎯⎯=104.9n=60, x¯=104.9 (c) ?=85, ?⎯⎯⎯=104.9n=85, x¯=104.9 (d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the quotes.)

A random sample is selected from a population with mean μ = 98 and standard deviation...

A random sample is selected from a population with mean μ = 98 and standard deviation σ = 10. Determine the mean and standard deviation of the x sampling distribution for each of the following sample sizes. (Round the answers to three decimal places.) (a) n = 8 μ = σ = (b) n = 18 μ = σ = (c) n = 38 μ = σ = (d) n = 55 μ = σ = (f) n = 110...

A random sample of ?n measurements was selected from a population with standard deviation ?=14.6 and...

A random sample of ?n measurements was selected from a population with standard deviation ?=14.6 and unknown mean ?. Calculate a 99% confidence interval for ? for each of the following situations: (a) ?=45, ?⎯⎯⎯=76.3 ____ ≤?≤ _______ (b) ?=65, ?⎯⎯⎯=76.3 ____ ≤?≤ ______ (c) ?=85, ?⎯⎯⎯=76.3 ______ ≤?≤ _______

A random sample of n observations is selected from a population with standard deviation σ =...

A random sample of n observations is selected from a population with standard deviation σ = 1. Calculate the standard error of the mean (SE) for these values of n. (Round your answers to three decimal places.) (a) n = 1 SE = (b) n = 2 SE = (c) n = 4 SE = (d) n = 9 SE = (e) n = 16 SE = (f) n = 25 SE = (g) n = 100 SE =

A random sample of ?n measurements was selected from a population with standard deviation ?=11.7 and...

A random sample of ?n measurements was selected from a population with standard deviation ?=11.7 and unknown mean ?. Calculate a 95% confidence interval for ? for each of the following situations: (a) ?=60, ?=85 ≤?≤ (b) ?=75, ?=85 ≤?≤ (c) ?=100, ?=85 ≤?≤

A random sample is selected from a population with mean μ = 102 and standard deviation...

A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. Determine the mean and standard deviation of the x sampling distribution for each of the following sample sizes. (Round the answers to three decimal places.) (a) n = 11 μ = σ = (b) n = 14 μ = σ = (c) n = 37 μ = σ = (d) n = 65 μ = σ = (f) n = 130...

A random sample of ? measurements was selected from a population with standard deviation σ=11.7 and...

A random sample of ? measurements was selected from a population with standard deviation σ=11.7 and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) ?=40, ?=72.1 ≤. μ ≤ (b) ?=60, ?=72.1 μ ≤ (c) ?=85, ?=72.1 ≤. μ. ≤

A simple random sample of 41men from a normally distributed population results in a standard deviation...

A simple random sample of 41men from a normally distributed population results in a standard deviation of 12.5 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.05 significance level to test the claim that pulse rates of men...

Subjects