In: Statistics and Probability
A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and unknown mean ?. Calculate a 99 % confidence interval for ? for each of the following situations:
(a) n=55, x¯=100.4
≤?≤
(b) n=75, x¯=100.4
≤?≤
(c) n=105, x¯=100.4
≤?≤
Solution :
Given that,
(a)
Sample size = n = 55
Z/2 = 2.576
Margin of error = E = Z/2* ( /n)
= 2.576 * (13.7 / 55)
Margin of error = E = 4.8
At 99% confidence interval estimate of the population mean is,
- E + E
100.4 - 4.8 100.4 + 4.8
95.6 105.2
(b)
Sample size = n = 75
Z/2 = 2.576
Margin of error = E = Z/2* ( /n)
= 2.576 * (13.7 / 75)
Margin of error = E = 4.1
At 99% confidence interval estimate of the population mean is,
- E + E
100.4 - 4.1 100.4 + 4.1
96.3 104.5
(c)
Sample size = n = 105
Z/2 = 2.576
Margin of error = E = Z/2* ( /n)
= 2.576 * (13.7 / 105)
Margin of error = E = 3.4
At 99% confidence interval estimate of the population mean is,
- E + E
100.4 - 3.4 100.4 + 3.4
97.0 103.8