In: Statistics and Probability
A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and unknown mean ?. Calculate a 99 % confidence interval for ? for each of the following situations:
(a) n=55, x¯=100.4
≤?≤
(b) n=75, x¯=100.4
≤?≤
(c) n=105, x¯=100.4
≤?≤
Solution :
Given that,
(a)
Sample size = n = 55
Z/2
= 2.576
Margin of error = E = Z/2*
(
/
n)
= 2.576 * (13.7 /
55)
Margin of error = E = 4.8
At 99% confidence interval estimate of the population mean is,
- E
+ E
100.4 - 4.8
100.4 + 4.8
95.6
105.2
(b)
Sample size = n = 75
Z/2
= 2.576
Margin of error = E = Z/2*
(
/
n)
= 2.576 * (13.7 /
75)
Margin of error = E = 4.1
At 99% confidence interval estimate of the population mean is,
- E
+ E
100.4 - 4.1
100.4 + 4.1
96.3
104.5
(c)
Sample size = n = 105
Z/2
= 2.576
Margin of error = E = Z/2*
(
/
n)
= 2.576 * (13.7 /
105)
Margin of error = E = 3.4
At 99% confidence interval estimate of the population mean is,
- E
+ E
100.4 - 3.4
100.4 + 3.4
97.0
103.8