For the given confidence level and values of x and n, find the following.x=48, n=97, confidence...

For the given confidence level and values of x and n, find the following.x=48, n=97, confidence level 99%

The point estimate for the given data is .4948.

The standard error for the given data is .0502.

(c) Find the margin of error. Round the answers to at least four decimal places, if necessary.

Solutions

Expert Solution

Given that,

Point estimate = sample proportion = = x / n = 0.4948

1 - = 1- 0.4948 =0.5052

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576 ( Using z table )

Margin of error = E = Z / 2 * ( $\sqrt$ ((( * (1 - )) / n)

= 2.576* ( $\sqrt$ (( 0.4948*0.5052) /97)

E = 0.1333

orchestra answered 1 year ago

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