In: Statistics and Probability
Use technology and the given confidence level and sample data to find the confidence interval for the population mean u.
Weight lost on a diet: 98% Confidence n=51 x=2.0 kg s=4.2 kg
What is the confidence interval for the population mean u?
___ kg < u < ___ kg
Solution :
Given that,
Point estimate = sample mean =
= 2
sample standard deviation = s = 4.2
sample size = n = 51
Degrees of freedom = df = n - 1 = 51 - 1 = 50
At 98% confidence level the t is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
t
/2,df = t0.01,50 = 2.403
Margin of error = E = t/2,df
* (s /
n)
= 2.403 * ( 4.2 /
51)
= 1.4
The 98% confidence interval estimate of the population mean is,
- E <
<
+ E
2 - 1.4 <
< 2 + 1.4
0.6 kg <
< 3.4 kg