Question

In: Math

v. Find the margin of error given the following: 99% confidence interval; n = 68, x...

v. Find the margin of error given the following: 99% confidence interval;

n = 68, x bar = 4156 and Std dev. = 839. ________

a. 1298    b.   237    c. 262    d. 8

vi. When do Type II errors occur?________

a. We decide to reject the null hypothesis when the null hypothesis was actually true.

b.   We fail to reject the null hypothesis when the null hypothesis is actually false.

c.   They occur in both cases.

vii. A standard score of z = 1.00 for an observation means: _________

a. The mean of the distribution lies 1 standard deviations below the observation.

b. The observation lies 1 standard deviations below the mean.

c. The observation lies 1 standard deviations above the mean.

d. The observation lies 1 means below the standard deviation.

viii. Given a 90% and a 95% confidence interval, which of the following is true?

  1.   The 90% confidence interval is wider than the 95% confidence interval.
  2. There is a better chance that the true mean will be found in the 95% confidence interval.
  1. None of the above.

ix. The number of hours per week that high school juniors watch TV is normally distributed with a mean of 8 hours and a standard deviation of 2 hours. If 100 students are chosen at random, find the probability that the mean for that sample is between 8.2 and 8.8

  1. 0.1598     b. 0.1586     c. 0.1156    d. 0.1152

Note: standard deviation/ the square root of n.

Check out the Central Limit Theorem

Solutions

Expert Solution


Related Solutions

Find the 80%, 95%, and 99% confidence intervals & margin error Create your own confidence interval...
Find the 80%, 95%, and 99% confidence intervals & margin error Create your own confidence interval (you cannot use 80%, 95%, and 99%) and make sure to show your work. Make sure to list the margin of error. 122 132 97 102 106 116 94 132 112 123 123 108 84 120 125 123 115 103 127 139 122 124 112 113 109 104 120 109 117 108 125 109 119 138 125 104 110 101 130 124 115 104...
1. If n= 360 and p-hat= 0.78, find the margin of error at a 99% confidence...
1. If n= 360 and p-hat= 0.78, find the margin of error at a 99% confidence level Give your answer to three decimals. 2. You are testing the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats. You sample 50 men, and 90% own cats. You sample 90 women, and 55% own cats. Find the pooled valuw of p, as a decimal, rounded to two decimal places. 3. Two...
Determine the margin of error for a 99​% confidence interval to estimate the population proportion with...
Determine the margin of error for a 99​% confidence interval to estimate the population proportion with a sample proportion equal to 0.80 for the following sample sizes. a. n=100             b. n=200             c. n=260
If n=530 and ˆpp^ (p-hat) =0.83, find the margin of error at a 99% confidence level...
If n=530 and ˆpp^ (p-hat) =0.83, find the margin of error at a 99% confidence level Give your answer to three decimals
Determine the margin of error for a 99​% confidence interval to estimate the population mean when...
Determine the margin of error for a 99​% confidence interval to estimate the population mean when s​ = 43 for the sample sizes below. ​a) n=12 ​b) n=25 ​c) n=46 ​a) The margin of error for a 99​% confidence interval when n=12 is _.
Determine the margin of error for a 99% confidence interval to estimate the population mean when...
Determine the margin of error for a 99% confidence interval to estimate the population mean when s=45 for the sample sizes of n=15, n=34, n=54. (Find the margin of error for each interval when n=x) Determine the margin of error for a confidence interval to estimate the population mean with n=24 and s=12.3 for confidence levels 80%, 90%, 99%.
Confidence Intervals (Proportions) 1 Find the margin of error and 95% confidence interval for the following...
Confidence Intervals (Proportions) 1 Find the margin of error and 95% confidence interval for the following surveys. Round all answers to 2 decimal places. (a) A survey of 500 people finds that 56% plan to vote for Smith for governor. Margin of Error (as a percentage): Confidence Interval: % to % (b) A survey of 1500 people finds that 47% support stricter penalties for child abuse. Margin of Error (as a percentage): Confidence Interval: % to % 2 Assume that...
Find the point estimate, the standard error, and the margin of error for the given confidence...
Find the point estimate, the standard error, and the margin of error for the given confidence level and values of x and n. x=45, n=97, confidence level 95% (a) Find the point estimate. (b) Find the standard error. (c) Find the margin of error.
Find the sample size needed to give, with 99% confidence a margin of error within +/-...
Find the sample size needed to give, with 99% confidence a margin of error within +/- 5 σ = 80 n = ____ σ = 30 n =____ σ =10 n = _____
find the sample size needed to give with 99% confidence a margin of error of plus...
find the sample size needed to give with 99% confidence a margin of error of plus or minus 5% when estimating proportion within plus minus 4% within plus minus 1%
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT