In: Statistics and Probability
Find the confidence interval for the given values of ?, ?, ?⎯⎯⎯, and confidence level.
?=2.1, ?=30, ?⎯⎯⎯=4.5, confidence = 0.92
Enter your answer by filling in the blanks ( ____ , ____ ). Round final answers to 2 decimal places.
Solution
Given that,
= 4.5
= 2.1
n = 30
At 92% confidence level the z is ,
=
1 - 92% = 1 - 0.92 = 0.08
/ 2 = 0.08 / 2 = 0.08
Z/2
= Z0.04 = 1.751
Margin of error = E = Z/2*
(
/n)
= 1.751 * (2.1 /
30 )
= 0.67
At 92% confidence interval estimate of the population mean is,
- E <
<
+ E
4.5 - 0.67 <
< 4.5 + 0.67
3.83 <
< 5.17
(3.83 , 5.17)