In: Statistics and Probability
Find the confidence interval for the given values of ?, ?, ?⎯⎯⎯, and confidence level.
?=21, ?=42, ?⎯⎯⎯=53, confidence = 0.89
Enter your answer by filling in the blanks ( ____ , ____ ). Round final answers to 2 decimal places.
Solution :
Given that,
Point estimate = sample mean =
= 53
Population standard deviation =
= 21
Sample size = n = 42
At 89% confidence level
= 1 - 89%
= 1 - 0.89 = 0.11
/2
= 0.055
Z/2
= Z0.055 = 1.598
Margin of error = E = Z/2
* (
/n)
= 1.598 * ( 21 / 42
)
= 5.18
At 89% confidence interval estimate of the population mean is,
- E < < + E
53 - 5.18 < < 53 + 5.18
47.82 <
< 58.18
( 47.82 , 58.18 )
The 89% confidence interval estimate of the population mean is : ( 47.82 , 58.18 )