Question

In: Statistics and Probability

Use technology and the given confidence level and sample data to find the confidence interval for...

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume that the population does not exhibit a normal distribution. Weight lost on a diet: 95 % confidence n equals 51 x overbar equals 4.0 kg s equals 6.9 kg What is the confidence interval for the population mean mu?? nothing kgless thanmuless than nothing kg ?(Round to one decimal place as? needed.)

Solutions

Expert Solution


Solution :

Given that,

= 4.0 kg

s = 6.9 kg

n = 51

Degrees of freedom = df = n - 1 = 51 - 1 = 50

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

  / 2 = 0.05 / 2 = 0.025

t /2,df = t0.025,50 =2.009

Margin of error = E = t/2,df * (s /n)

= 2.009* * (6.9 / 51)

= 1.9

The 95% confidence interval estimate of the population mean is,

- E < < + E

4.0 - 1.9 < < 4.0 + 1.9

2.1 < < 5.9

(2..1, 5.9 )


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