Question

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume that the population does not exhibit a normal distribution. Weight lost on a diet: 95 % confidence n equals 51 x overbar equals 4.0 kg s equals 6.9 kg What is the confidence interval for the population mean mu?? nothing kgless thanmuless than nothing kg ?(Round to one decimal place as? needed.)

Answer 1

Solution :

Given that,

= 4.0 kg

s = 6.9 kg

n = 51

Degrees of freedom = df = n - 1 = 51 - 1 = 50

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

  / 2 = 0.05 / 2 = 0.025

t _/2,df = t_0.025,50 =2.009

Margin of error = E = t_/2,df * (s /n)

= 2.009* * (6.9 / 51)

= 1.9

The 95% confidence interval estimate of the population mean is,

- E < < + E

4.0 - 1.9 < < 4.0 + 1.9

2.1 < < 5.9

(2..1, 5.9 )