1) Design and draw a serial dilution to go from 4x10^8 cells/ml to 2x10^5 cells/ml. Indicate...

1) Design and draw a serial dilution to go from 4x10^8 cells/ml to 2x10^5 cells/ml. Indicate DF, TDF, and org/ml at each step.

Expert Solution

Given concentration: 4*10⁸ cells/mL

The required concentration: 2*10⁵ cells/mL

The serial dilution can be done as shown below.

1^st dilution: 4*10⁸ * 1/2 = 2*10⁸ cells/mL, DF = 1: 3, TDF = 1: 3

2^nd dilution: 2*10⁸ * 1/2 = 1*10⁸ cells/mL, DF = 1: 3, TDF = 1: 3 * 1: 3, i.e. 1: 9

3^nd dilution: 1*10⁸ * 1/2 = 5*10⁷ cells/mL, DF = 1: 3, TDF = 1: 3 * 1: 3 * 1: 3, i.e. 1: 27

4^th dilution: 5*10⁷ * 1/2 = 2.5*10⁷ cells/mL, DF = 1: 3, TDF = 1: 3 * 1: 3 * 1: 3 * 1: 3, i.e. 1: 81

5^th dilution: 2.5*10⁷ * 1/5 = 5*10⁶ cells/mL, DF = 1: 6, TDF = 1: 3 * 1: 3 * 1: 3 * 1: 3 * 1: 6, i.e. 1: 486

6^th dilution: 5*10⁶ * 1/5 = 1*10⁶ cells/mL, DF = 1: 6, TDF = 1: 3 * 1: 3 * 1: 3 * 1: 3 * 1: 6 * 1: 6, i.e. 1: 2916

7^th dilution: 1*10⁶ * 1/5 = 2*10⁵ cells/mL, DF= 1: 6, TDF = 1: 3 * 1: 3 * 1: 3 * 1: 3 * 1: 6 * 1: 6 * 1: 6, i.e. 1: 17496

queen_honey_blossom answered 2 years ago

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