Consider the following dilution steps from a 3.51 M stock solution of H2SO4. 1. 25. mL...

Consider the following dilution steps from a 3.51 M stock solution of H2SO4. 1. 25. mL of the 3.51 M stock solution is diluted to 150. mL to make soln2. 2. 35. mL of soln2 is diluted to 200. mL to make soln3. 3. 45. mL of soln3 is diluted to 250. mL to make soln4. 4. 50. mL of soln4 is diluted to 300. mL to make soln5. • Calculate the concentration, in M, for soln5. • Derive a single equation to calculate the concentration of soln5 using only the molatiry of the stock solution and the various volumes.

Solutions

Expert Solution

The answer is

thank you.

queen_honey_blossom answered 1 year ago

Next > < Previous

Related Solutions

Consider a solution formed by mixing 50.0 mL of 0.100 M H2SO4, 30.0 mL of 0.1000...

Consider a solution formed by mixing 50.0 mL of 0.100 M H2SO4, 30.0 mL of 0.1000 M HOCl, 25.0 mL of 0.200 M NaOH, 25.0 mL 0.100 M Ba(OH)2, and 10.0 mL of 0.150 M KOH. Calculte the pH of this solution. Ka (HOCl) = 3.5 x 10-8 What is the pH?

Titration of a 15.0 mL solution of KOH requires 17.0 mL of 0.0250 M H2SO4 solution....

Titration of a 15.0 mL solution of KOH requires 17.0 mL of 0.0250 M H2SO4 solution. What is the molarity of the KOH solution? M=?

For the titration of 50.00 mL of a 0.1000 M solution of compound H2SO4 with a...

For the titration of 50.00 mL of a 0.1000 M solution of compound H2SO4 with a 0.2000 M solution of compound NaOH in the following table. For each titration, calculate the pH after the addition of 0.00, 20.00, 25.00, 37.50, 50.00, and 60.00 mL of com- pound NaOH. Please explain all the steps.

100 mL of 0.1 M NaOH solution was poured into 20 mL of 0.2 M H2SO4...

100 mL of 0.1 M NaOH solution was poured into 20 mL of 0.2 M H2SO4 solution and mixed well. What was the final pH of the mixture?

A 30.00 mL solution of 0.235 M CH2NH2 was titrated with 0.150 M H2SO4. a) Calculate...

A 30.00 mL solution of 0.235 M CH2NH2 was titrated with 0.150 M H2SO4. a) Calculate the pH of the 30.00 mL solution of 0.235 M CH2NH2 b) Calculate the volume of 0.150 M H2SO4 required to neutralize the 30 mL solution of 0.235 M CH2NH2. c) Calculate the volume of 0.150 M H2SO4 required to neutralize half the mole of CH2NH2 present 30 Ml solution of 0.235 M CH2NH2 d) Calculte the pH of the solution in (c). e)...

The concentration of the initial stock solution is 3.00 M. The first dilution is made by...

The concentration of the initial stock solution is 3.00 M. The first dilution is made by measuring 10.00 mL with a volumetric pipet and diluting in a 100 mL volumetric flask. What is the concentration of the first solution? The second solution is made by measuring 25.00 mL of the first solution and diluting in a 100 mL volumetric flask. What is the concentration of the second solution? The third solution is made by measuring 50.00 mL of the second...

A chemist wants to prepare a stock solution of H2SO4 so that samples of 20 mL...

A chemist wants to prepare a stock solution of H2SO4 so that samples of 20 mL will produce a solution with a concentration of 0.2 M when added to 80.0 mL of water. What should the molarity of the stock solution be?

13. A 15.0 mL NaOH solution is required to neutralize 10.0 mL of 0.100 M H2SO4(aq)...

13. A 15.0 mL NaOH solution is required to neutralize 10.0 mL of 0.100 M H2SO4(aq) solution. What is the concentration of NaOH solution used? 2NaOH (aq) + H2SO4(aq) → Na2SO4(aq) + 2H2O(l)

if 25 ml of 1 mol/L H2SO4 was added to 75 ml of 1 mol/L NaOH...

if 25 ml of 1 mol/L H2SO4 was added to 75 ml of 1 mol/L NaOH what is the expected temperature change of the solution?

Consider recording an emission spectrum of a solution of quinine in 0.05 M H2SO4, using a...

Consider recording an emission spectrum of a solution of quinine in 0.05 M H2SO4, using a spectrofluorimeter. As a preliminary step you record a spectrum of the blank solution. With the excitation monochromator set at 395 nm and scanning the emission monochromator from 404 nm to 800 nm, you observe three sharp peaks. A. At what wavelength would Rayleigh scattering appear in the emission spectrum as a result of spectral overlap from the second order of the grating? B. At...

Subjects