Question

Complete a 1:5 dilution series with each tube containing a final bolune of 10mL. Indicate the dilution factor of each tube relative to the stock and the volume of water and solution in each tube. The first tube represebts the concentrated stock solution, make dilutions in the reaminubg for tubes. Please show work

Answer 1

Answer - Dilution ratio is 1:5 that is = 1/5 dilution

For 1/5 dilution we take 1 part sample and 4 parts diluent in a total of 5 parts.

If final Volume is = 10 ml, then

We need 1/5 of 10 ml = 2 ml sample.

To bring this 2 ml sample up to a total volume of 10 ml

We must add 10 ml - 2 ml = 8 ml diluent.

So Solute is =2 ml and Solvent is = 8 ml.

The dilution factor can be expressed using exponents: 1:5 would be 5e−1 (5−1 i.e. one-fifth:one)

Dilution factor = (1:n+1) ; here n+1 =the total volume of solute + solvent. In serial dilution assays, the given dilution factor often means the ratio to the final volume, not to just the solvent.

Dilution Factor = Initial Volume /Final Volume =

DF=Vi/Vf

If we add  a 1 mL sample to 9 mL of diluent to get 10 mL of solution,

DF=Vi/Vf = 1mL/10mL=110. This is a 1:10 dilution further it would be 0.1/10 =1/100 where stock solution is= 0.01stock per ml and for successive dilution

0.01/10 that is 1/1000