Question
In: Chemistry
Of the original “undiluted” sample from Question 1(see below), 10L of a 5-to-1 dilution were used...
Of the original “undiluted” sample from Question 1(see below), 10L of a 5-to-1 dilution were used to measure protein concentration. With the use of a standard curve, this is found to be 140g. What is the specific activity of the original sample? Question 1 referenced above: Assayed for LDH activity were 5L of a sample that was diluted 6 to 1. The activity in the reaction vessel, which has a volume of 3 mL, is 0.30 U. What is the A/min observed? What is the relative activity of the original sample? (I calculated a relative activity of 360 U/mL from question 1 with an A/min change of 0.622) Using this information I get the following: 140ug/uL=14ug/uL=14mg/mL x 5 dilutions= 70mg/mL For specific activity= (U/mL)/(mg/mL)=(360 U/mL)/(70mg/mL)= 5.14 U/mg Does this look correct?
Solutions
queen_honey_blossom answered 1 year agoRelated Solutions
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