In: Computer Science
Assume that you have a 12-bit floating point number system, similar to the IEEE floating point standard, with the format shown below and a bias of 7. The value of a floating point number in this system is represented as
FP = (-1)^S X 1.F X 2^(E-bias)
for the floating point numbers A = 8.75 and B = -5.375. The binary representation of A is given as
A = 0101 0000 1100
Show the hexidecimal representation of B.

0xCAC
Explanation:
-------------
-5.375
Converting 5.375 to binary
Convert decimal part first, then the fractional part
> First convert 5 to binary
Divide 5 successively by 2 until the quotient is 0
> 5/2 = 2, remainder is 1
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 101
So, 5 of decimal is 101 in binary
> Now, Convert 0.37500000 to binary
> Multiply 0.37500000 with 2. Since 0.75000000 is < 1. then add 0 to result
> Multiply 0.75000000 with 2. Since 1.50000000 is >= 1. then add 1 to result
> Multiply 0.50000000 with 2. Since 1.00000000 is >= 1. then add 1 to result
> This is equal to 1, so, stop calculating
0.375 of decimal is .011 in binary
so, 5.375 in binary is 00000101.011
-5.375 in simple binary => 101.011
so, -5.375 in normal binary is 101.011 => 1.01011 * 2^2
12-bit format:
--------------------
sign bit is 1(-ve)
exponent bits are (7+2=9) => 1001
Divide 9 successively by 2 until the quotient is 0
> 9/2 = 4, remainder is 1
> 4/2 = 2, remainder is 0
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 1001
So, 9 of decimal is 1001 in binary
frac/significant bits are 0101100
so, -5.375 in 12-bit format is 1 1001 0101100
Hexadecimal Binary
0 0000
1 0001
2 0010
3 0011
4 0100
5 0101
6 0110
7 0111
8 1000
9 1001
A 1010
B 1011
C 1100
D 1101
E 1110
F 1111
Use this table to convert from binary to hexadecimal
Converting 110010101100 to hexadecimal
1100 => C
1010 => A
1100 => C
So, in hexadecimal 110010101100 is 0xCAC
in hexadecimal it is 0xCAC