Question

In: Computer Science

In this question, you are provided with an IEEE-754 floating-point number in the form of 8...

In this question, you are provided with an IEEE-754 floating-point number in the form of 8 hexadecimal digits.

You are asked to decode this value into its decimal representation.

You MUST report your answer as a real number.

Do NOT use scientific notation.

Do NOT round or truncate your answer.

Do NOT add any spaces or commas to your answer.

If the converted number is positive, do NOT add the plus sign.

Convert, i.e., decode, 0x48801002 from the 32-bit single-precision IEEE-754 FP representation into decimal representation.   

Solutions

Expert Solution

Answer: 262272.0625

Explanation:
-------------
Hexadecimal     Binary
    0           0000
    1           0001
    2           0010
    3           0011
    4           0100
    5           0101
    6           0110
    7           0111
    8           1000
    9           1001
    A           1010
    B           1011
    C           1100
    D           1101
    E           1110
    F           1111
Use this table to convert from hexadecimal to binary
Converting 48801002 to binary
4 => 0100
8 => 1000
8 => 1000
0 => 0000
1 => 0001
0 => 0000
0 => 0000
2 => 0010
So, in binary 48801002 is 01001000100000000001000000000010
01001000100000000001000000000010
0 10010001 00000000001000000000010
sign bit is 0(+ve)
exp bits are 10010001
   => 10010001
   => 1x2^7+0x2^6+0x2^5+1x2^4+0x2^3+0x2^2+0x2^1+1x2^0
   => 1x128+0x64+0x32+1x16+0x8+0x4+0x2+1x1
   => 128+0+0+16+0+0+0+1
   => 145
in decimal it is 145
so, exponent/bias is 145-127 = 18
frac bits are 0000000000100000000001

IEEE-754 Decimal value is 1.frac * 2^exponent
IEEE-754 Decimal value is 1.0000000000100000000001 * 2^18
1.0000000000100000000001 in decimal is 1.000488519668579
   => 1.0000000000100000000001
   => 1x2^0+0x2^-1+0x2^-2+0x2^-3+0x2^-4+0x2^-5+0x2^-6+0x2^-7+0x2^-8+0x2^-9+0x2^-10+1x2^-11+0x2^-12+0x2^-13+0x2^-14+0x2^-15+0x2^-16+0x2^-17+0x2^-18+0x2^-19+0x2^-20+0x2^-21+1x2^-22
   => 1x1+0x0.5+0x0.25+0x0.125+0x0.0625+0x0.03125+0x0.015625+0x0.0078125+0x0.00390625+0x0.001953125+0x0.0009765625+1x0.00048828125+0x0.000244140625+0x0.0001220703125+0x6.103515625e-05+0x3.0517578125e-05+0x1.52587890625e-05+0x7.62939453125e-06+0x3.814697265625e-06+0x1.9073486328125e-06+0x9.5367431640625e-07+0x4.76837158203125e-07+1x2.384185791015625e-07
   => 1+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.00048828125+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.0+0.0+2.384185791015625e-07
   => 1.000488519668579
so, 1.000488519668579 * 2^18 in decimal is 262272.0625
so, 01001000100000000001000000000010 in IEEE-754 single precision format is 262272.0625
Answer: 262272.0625




Related Solutions

Convert the following floating-point number (stored using IEEE floating-point standard 754) to a binary number in...
Convert the following floating-point number (stored using IEEE floating-point standard 754) to a binary number in non-standard form. 0100_0001_1110_0010_1000_0000_0000_0000
Convert the following number into 32bit IEEE 754 floating point representation. 0.000101
Convert the following number into 32bit IEEE 754 floating point representation. 0.000101
convert 0x41BA8000 to IEEE-754 floating-point value
convert 0x41BA8000 to IEEE-754 floating-point value
convert 0x41BA8000 to IEEE-754 floating-point value
convert 0x41BA8000 to IEEE-754 floating-point value
convert 0x41BA8000 to IEEE-754 floating-point value
convert 0x41BA8000 to IEEE-754 floating-point value
The number –11.375 (decimal) represented as a 32-bit floating-point binary number according to the IEEE 754...
The number –11.375 (decimal) represented as a 32-bit floating-point binary number according to the IEEE 754 standard is
Convert 0.875 to an IEEE 754 single-precision floating-point number. Show the sign bit, the exponent, and...
Convert 0.875 to an IEEE 754 single-precision floating-point number. Show the sign bit, the exponent, and the fraction. Convert -3.875 to an IEEE 754 double-precision floating-point number. Show the sign bit, the exponent, and the fraction Convert the IEEE 754 single-precision floating-point numbers 42E4800016 and 0080000016 to their corresponding decimal numbers.
verilog code to implement 32 bit Floating Point Adder in Verilog using IEEE 754 floating point...
verilog code to implement 32 bit Floating Point Adder in Verilog using IEEE 754 floating point representation.
3. IEEE Floating Point Representation What decimal number does the 32-bit IEEE floating point number 0xC27F0000...
3. IEEE Floating Point Representation What decimal number does the 32-bit IEEE floating point number 0xC27F0000 represent? Fill in the requested information in the blanks below. What is the sign of the number (say positive or negative): What is the exponent in decimal format: What is the significand in binary: What is the value of the stored decimal number in decimal (final answer): Credit will be given for your final answer in the blanks and the work shown below.
Assume that you have a 12-bit floating point number system, similar to the IEEE floating point...
Assume that you have a 12-bit floating point number system, similar to the IEEE floating point standard, with the format shown below and a bias of 7. The value of a floating point number in this system is represented as    FP = (-1)^S X 1.F X 2^(E-bias) for the floating point numbers A = 8.75 and B = -5.375. The binary representation of A is given as A = 0101 0000 1100 Show the hexidecimal representation of B.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT