Question

Assume C₁₂H₂₂O₁₁ ​=.9913g

Calulate the Moles contianed in the sample of C₁₂H₂₂O₁₁ .

Calculate the Moles of each element in C₁₂H₂₂O₁₁.

Calucalte the number of atoms of each Element in C₁₂H₂₂O₁₁ .

Answer 1

A)

Molar mass of C12H22O11,

MM = 12*MM(C) + 22*MM(H) + 11*MM(O)

= 12*12.01 + 22*1.008 + 11*16.0

= 342.296 g/mol

mass(C12H22O11)= 0.9913 g

number of mol of C12H22O11,

n = mass of C12H22O11/molar mass of C12H22O11

=(0.9913 g)/(342.296 g/mol)

= 0.00290 mol

B)

moles of C = 12*number of mol of C12H22O11

= 12*0.00290 mol

= 0.0348 mol

moles of H = 22*number of mol of C12H22O11

= 22*0.00290 mol

= 0.0638 mol

moles of O = 11*number of mol of C12H22O11

= 11*0.00290 mol

= 0.0319 mol

C)

number of atom of C = moles of C * 6.022*10^23 atoms

= 0.0348 * 6.022*10^23 atoms

= 2.096*10^22 atoms

number of atom of H = moles of H * 6.022*10^23 atoms

= 0.0638 * 6.022*10^23 atoms

= 3.842*10^22 atoms

number of atom of O = moles of O * 6.022*10^23 atoms

= 0.0319 * 6.022*10^23 atoms

= 1.921*10^22 atoms