Question

Calculate each of the following quantities in 1.80 moles H3PO4:

Part A moles of H nothing moles SubmitRequest Answer Part B moles of O nothing moles SubmitRequest Answer Part C atoms of P nothing atoms SubmitRequest Answer Part D atoms of O nothing atoms SubmitRequest Answer

Answer 1

A)

one mole of H3PO4 contains 3 mole of H

use:

number of moles of H = 3 * number of moles of H3PO4

= 3 * 1.80

= 5.40

Answer: 5.40

B)

one mole of H3PO4 contains 4 mole of O

use:

number of moles of O = 4 * number of moles of H3PO4

= 4 * 1.80

= 7.20

Answer: 7.20

C)

one mole of H3PO4 contains 1 moles of P

use:

number of moles of P = 1 * number of moles of H3PO4

= 1 * 1.80

= 1.80

Number of atom of P = mol of P * Avogadro’s number

= 1.80 * 6.022*10^23

= 1.08*10^24 atoms

Answer: 1.08*10^24 atoms

D)

Number of atom of O = mol of O * Avogadro’s number

= 7.20 * 6.022*10^23

= 4.34*10^24 atoms

Answer: 4.34*10^24 atoms