Two balls connected by a rod, as shown in the figure below (Ignore rod’s mass).

Two balls connected by a rod, as shown in the figure below (Ignore rod’s mass). Mass of ball X is 8kg and the mass of ball Y is 5 kg What is the moment of inertia of the system about AB?

Solutions

Expert Solution

Given

The rotation axis is AB

mX = 8kg mass of object x

mY = 5kg mass of object y

rX = 10cm = 0.1 distance from centre object x

rY = 40cm = 0.4m distance from centre object y

Solution:

I = mX rX^2 + mY rY^2

I = (0.8)× (0.1)^2 + (0.8)× (0.4)^2

I = 8 × 10^-3 + 0.128

I = 0.136kg m2.

I = mX rX^2 + mY rY^2

Mx- mass of 1 st object

My- mass of 2 nd object

X,Y- distance from centre for both objects

Naveen yadav answered 3 years ago

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