In: Statistics and Probability
A group of young business women wish to open a high fashion boutique in a vacant store but only if the average income of households in the area is at least 25,000. A random sample of 9 households showed the following results.
$28,000 $24,000 $26,000 $25,000
$23,000 $27,000 $26,000 $22,000
$24,000
Assume the population of income is normally distributed. Using the critical value approach, test the hypothosis at the 5% level of significance.
null hypothesis: Ho: μ | = | 25000 | |
Alternate Hypothesis: Ha:μ | < | 25000 | |
0.05 level with right tailed test and n-1= 8 df, critical t= | 1.860 | ||
Decision rule : reject Ho if test statistic t>1.860 | |||
population mean μ= | 25000 | ||
sample mean x= | 25000.00 | ||
sample size n= | 9 | ||
sample std deviation s= | 1936.492 | ||
std error sx=s/√n= | 645.4972 | ||
test stat t='(x-μ)*√n/s= | 0.00 |
since test statistic does not falls in rejection region we fail to reject null hypothesis |
we do not have have sufficient evidence to conclude that average income of households in the area is less than 25000 |