The triprotic acid H3A has ionization constants of Ka1 = 6.2× 10–3, Ka2 = 9.6× 10–9,...

The triprotic acid H3A has ionization constants of Ka1 = 6.2× 10–3, Ka2 = 9.6× 10–9, and Ka3 = 6.3× 10–12. Calculate the following values for a 0.0790 M solution of NaH2A

A)Calculate the following values for a 0.0790 M solution of NaH2A.

H⁺=?

H₂A^-/H₃A=?

B)Calculate the following values for a 0.0790 M solution of Na2HA.

H⁺=?

HA^2-/H₂A^-=?

Expert Solution

queen_honey_blossom answered 1 year ago

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