In: Statistics and Probability
DATA SET 2
The following data were obtained from a research study comparing two treatment conditions. Analyze this data to determine whether you will reject or fail to reject the null hypothesis based upon your results. Two-tailed test. Alpha = .05 (Please show work)
Treatment 1 | Treatment 2 |
10 | 7 |
8 | 4 |
7 | 9 |
9 | 3 |
13 | 7 |
7 | 6 |
6 | 10 |
12 | 2 |
n1 = 8
= 9
s1 = 2.5071
n2 = 8
= 6
s2 = 2.8284
The null and alternative hypothesis is
For doing this test first we have to check the two groups have population variances are equal or not.
Null and alternative hypothesis is
Test statistic is
F = largest sample variance / Smallest sample variances
F = 2.8284^2 / 2.5071^2 = 1.27
Degrees of freedom => n1 - 1 , n2 - 1 => 8 - 1 , 8 - 1 => 7 , 7
Critical value = 3.787 ( Using f table)
Critical value > test statistic so we fail to reject null hypothesis.
Conclusion: The population variances are equal.
So we have to use here pooled variance.
Test statistic is
Degrees of freedom = n1 + n2 - 2 = 8 + 8 - 2 = 14
Critical value = 2.145 ( Using t table)
| t | > critical value we reject null hypothesis.