In: Math
The following data were obtained from a repeated-measures study comparing 3 treatment conditions. Use a repeated-measures ANOVA with a=.05 to determine whether there are significant mean differences among the three treatments (do all 4 steps of conducting a hypothesis test!!):
Person |
Treatment 1 |
Treatment 2 |
Treatment 3 |
Person Totals |
|
A |
0 |
2 |
4 |
P=6 |
N=15 |
B |
0 |
3 |
6 |
P=9 |
G=60 |
C |
3 |
7 |
8 |
P=18 |
|
D |
0 |
7 |
5 |
P=12 |
|
E |
2 |
6 |
7 |
P=15 |
|
M=1 |
M=5 |
M=6 |
|||
T=5 |
T=25 |
T=30 |
|||
SS=8 |
SS=22 |
SS=10 |
null hypothesis:Ho: all three treatments have equal means
alternate hypothesis:Ha: there are significant mean differences among the three treatments
applying two way ANOVA:
for (2,8) degree of freedom and 0.05 level critical value F=4.459
as test statsitic 28.0 is greater than crtiical value we reject null hypothesis
we have sufficient evidence at 0.05 level to conclude that there are significant mean differences among the three treatments