In: Statistics and Probability
The following data represent the results from an independent-measures study comparing two treatment conditions.
Treatment One |
Treatment Two |
---|---|
2.5 | 1.7 |
3.9 | 4.5 |
4.3 | 3.2 |
4.6 | 2.9 |
2.9 | 3.2 |
5.1 | 3.8 |
4.2 | 2.3 |
Using technology, run the One-way ANOVA Test for this data:
F-ratio:
p-value:
Now, run the Two Independent Sample t test on the same
data:
Note: Do this with "pooled variances" since one assumption we
make with ANOVA is that the variances for each group are
equal.
t-statistic:
p-value:
Answer:
Given Data
For the given data set the One way ANOVA test is conducted with the help of excel data analysis tool which results in the following output:
ANOVA : Single Factor | |||||
Summary | |||||
Groups | Count | Sum | Average | Variance | |
Treatment One | 7 | 27.5 | 3.9286 | 0.8557 | |
Treatment Two | 7 | 21.6 | 3.0857 | 0.8514 | |
ANOVA | |||||
Source of Variation | SS | df | MS | F | P -Value |
Between Groups | 2.4864 | 1 | 2.4864 | 2.91297 | 0.11359 |
Within Groups | 10.2429 | 12 | 0.8536 | ||
Total | 12.7293 | 13 |
From the ANOVA output above the F-ratio 2.91297 and
The P-value is 0.11359
b) Now we run a T-test for the sample assuming equality of variances and Independent sample using the excel tool data analysis, the following output is obtained as:
t test :Two sample Assuming Equal variances | ||
Treatment One | Treatment Two | |
Mean | 3.9286 | 3.0857 |
Variance | 0.8557 | 0.8514 |
Observations | 7 | 7 |
df | 12 | |
t stat | 1.7067 | |
P(T <=t) two tail | 0.1136 | |
t critical two tail |
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