In: Statistics and Probability
Use the confidence level and sample data to find a confidence interval for estimating the population . Round your answer to the same number of decimal places as the sample mean. Test scores: n= 105 x bar =70.5, sigma =6.8; 99% confidence
Solution :
Given that,
= 70.5
= 6.8
n = 105
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Margin of error = E = Z/2* (/n)
= 2.576 * (6.8 / 105 )
= 1.7
At 99% confidence interval estimate of the population mean is,
- E < < + E
70.5 - 1.7 < < 70.5 + 1.7
68.8 < < 72.2
(68.8, 72.2)