Question
In: Physics
A rock is suspended by a light string. When the rock is in air, the tension...
A rock is suspended by a light string. When the rock is in air, the tension in the string is 45.0 N . When the rock is totally immersed in water, the tension is 29.2 N . When the rock is totally immersed in an unknown liquid, the tension is 21.0 N .
What is the density of the unknown liquid?
Solutions
Expert Solution
Gravitational acceleration = g = 9.81 m/s2
Density of water = 
w = 1000
kg/m3
Density of unknown liquid =
Weight of the rock = Tension in string in air = W = 45 N
Volume of the rock = V
Tension when the rock is immersed in water = T1 = 29.2 N
Buoyancy force on the rock in water = F1 = wVg
The weight of the rock is supported by the tension and the buoyancy force on it.
W = T1 + F1
W = T1 + wVg
45 = 29.2 + (1000)(9.81)V
V = 1.611 x 10-3 m3
Tension when the rock is immersed in the unknown liquid = T2 = 21 N
Buoyancy force on the rock in the unknown liquid = F2
= Vg
The weight of the rock is supported by the tension and the buoyancy force on it.
W = T2 + F2
W = T2 + Vg
45 = 21 + (9.81)(1.611x10-3)
= 1518.61
kg/m3
Density of the unknown liquid = 1518.61 kg/m3
genius_generous answered 1 hour agoRelated Solutions
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