In: Math
Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu μ. Assume that the population does not exhibit a normal distribution. Weight lost on a diet:
90% confidence n=41 x x=3.0 kg s=5.6 kg
What is the confidence interval for the population mean mu μ? _<μ<_
Solution :
Given that,
Point estimate = sample mean = = 3.0
sample standard deviation = s = 5.6
sample size = n = 41
Degrees of freedom = df = n - 1 = 40 - 1 = 40
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
t /2,df = t0.05,40 = 1.684
Margin of error = E = t/2,df * (s /n)
= 1.684 * (5.6 / 41)
= 1.5
The 90% confidence interval estimate of the population mean is,
- E < < + E
3.0 - 1.5 < < 3.0 + 1.5
1.5 < < 4.5