In: Statistics and Probability
22.HE.A: It has been assumed that children are born with equal frequency with respect to days of the week. Randomly selected birth records are obtained and results are listed in the table below.
Sunday |
Monday |
Tuesday |
Wednesday |
Thursday |
Friday |
Saturday |
36 |
55 |
62 |
60 |
60 |
58 |
48 |
a)
Chi Square test of goodness of fit
b)
Null and Alternative Hypotheses
c)
The following conditions are all satisfied:
d)
Based on the information provided, the significance level is α=0.05, the number of degrees of freedom is df=7−1=6
e)
Test Statistics
The Chi-Squared statistic is computed as follows:
f)
Maximum - Sunday
Minimum - Monday
g)
At 5% level of significance, since it is observed that χ2=9.472≤χc2=12.592, it is then concluded that the null hypothesis is not rejected.Therefore, there is NOT enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the \α=0.05 significance level.
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