In: Statistics and Probability
A sports researcher gave a standard written test of eating habits to 12 randomly selected professionals, four each from baseball, football, and basketball. The results were as follows:
Eating Habit Scores
Baseball Players: 34, 18, 21, 65
Football Players: 27, 28, 67, 42
Basketball Players: 35,44,47,41
Is there a difference in eating habits among professionals in the three sports (using the 0.05 significance level)?
Please use the 5 steps to solve this equation.
Please include the S^2 between / S^within, graphs, and all information neceissary to compute this problem
| count, ni = | 4 | 4 | 4 | ||
| mean , x̅ i = | 34.500 | 41.00 | 41.75 | ||
| std. dev., si = | 21.486 | 18.637 | 5.123 | ||
| sample variances, si^2 = | 461.667 | 347.333 | 26.250 | ||
| total sum | 138 | 164 | 167 | 469 | |
| grand mean , x̅̅ = | Σni*x̅i/Σni = | 39.08 | 
| square of deviation of sample mean from grand mean,( x̅ - x̅̅)² | 21.007 | 3.674 | 7.111 | ||
| TOTAL | |||||
| SS(between)= SSB = Σn( x̅ - x̅̅)² = | 84.028 | 14.694 | 28.444 | 127.1667 | |
| SS(within ) = SSW = Σ(n-1)s² = | 1385.000 | 1042.000 | 78.750 | 2505.7500 | 
no. of treatment , k =   3
df between = k-1 =    2
N = Σn =   12
df within = N-k =   9
  
mean square between groups , MSB = SSB/k-1 =   
63.5833
  
mean square within groups , MSW = SSW/N-k =   
278.4167
  
F-stat = MSB/MSW =    0.2284
P value =   0.8003
------------------------
Ho: µ1=µ2=µ3
H1: not all means are equal
| SS | df | MS | F | p-value | F-critical | |
| Between: | 127.17 | 2 | 63.58 | 0.23 | 0.8003 | 4.26 | 
| Within: | 2505.75 | 9 | 278.42 | |||
| Total: | 2632.92 | 11 | ||||
| α = | 0.05 | |||||
| conclusion : | p-value>α , do not reject null hypothesis | 
There is insufficient evidence that means are different.