The state test scores for
12 randomly selected high school seniors are shown on the
right....
The state test scores for
12 randomly selected high school seniors are shown on the
right. Complete parts (a) through (c) below.
Assume the population is normally distributed.
1420
1220
982
695
720
837
724
750
542
627
1444
941
(a) Find the sample mean.
x overbar x =
(Round to one decimal place as needed.)
(b) Find the sample standard deviation.
s =
(Round to one decimal place as needed.)
(c) Construct a 90% confidence interval for the population
mean μ.
A 90% confidence interval for the population mean is
(Round to one decimal place as needed.)
Solutions
Expert Solution
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The state test scores for 12 randomly selected high school
seniors are shown on the right. Complete parts (a) through (c)
below.
Assume the population is normally distributed.
12 scores-
1430
1220
985
694
729
837
724
750
544
621
1443
949
1) find the sample mean
2) find the standard deviation
3) construct a 90% confidence interval for the population
mean
The state test scores for 12 randomly selected high school
seniors are shown on the right. Complete parts (a) through (c)
below. Assume the population is normally distributed. 1420 1225 988
691 730 833 721 748 550 628 1445 946 (a) Find the sample mean. (b)
find the standard deviation (c) construct 90% confidence
interval.
10)
The SAT scores for 12 randomly selected seniors at a particular
high school are given below. Assume that the SAT scores for seniors
at this high school are normally distributed.
1,271
1,288
1,278
616
1,072
944
1,048
968
931
990
891
849
a) Find a 95% confidence interval for the true mean SAT score
for students at this high school.
b) Provide the right endpoint of the interval
as your answer.
Round your answer to the nearest whole
number.
Assignment 1:
It is known that achievement test scores of all high school
seniors in a state (in the US) have mean 60 and variance 64. On a
large high school, located in a low socio economic area, a small
group of senior students set out to investigate the performance of
their own school. They collected a random sample of ??=100
achievement test scores from fellow students. Analyzing the
results, it was found that the sample mean achievement test score...
A study compared the drug use of 288 randomly selected high
school seniors exposed to a drug education program (DARE) and 335
randomly selected high school seniors who were not exposed to such
a program. Data for marijuana use are given in the accompanying
table.
sample size
number who use marijuana
exposed to DARE
288
137
not exposed to DARE
335
181
At the 5% significance level, is there convincing evidence that the
proportion using marijuana is lower for students...
An article compared the drug use of 288 randomly selected high
school seniors exposed to a drug education program (DARE) and 335
randomly selected high school seniors who were not exposed to such
a program. Data for marijuana use are given in the accompanying
table.
n
Number Who
Use Marijuana
Exposed
to DARE
288
142
Not
Exposed to DARE
335
177
Is there evidence that the proportion using marijuana is lower
for students exposed to the DARE program? Use α...
Scholastic Aptitude Test (SAT) mathematics scores of a random
sample of 100 high school seniors in the state of Texas are
collected, and the sample mean and standard deviation are found to
be 520 and 80, respectively. Find a 95% confidence interval on the
mean SAT mathematics score for seniors in the state of Texas.
I/ The following data are ACT test scores from a group of high
school seniors: 30, 25, 29, 32, 27, 25, 24, 18, 26 1/ Find the mode
2/ Find the mean 3/ Construct a boxplot (clearly label all 5
specific values) 4/ Calculate the standard deviation for the data
set
The SAT scores of 20 randomly selected high school students has
a mean of =1,185 and a sample standard deviation s=168.0. Construct
an 98% confidence interval for the true population mean and
interpret this interval
The SAT scores of 20 randomly selected high school students has
a mean of =1,185 and a sample standard deviation s=168.0. Construct
an 98% confidence interval for the true population mean and
interpret this interval