Question

In: Statistics and Probability

A sports researcher gave a standard questionnaire of eating habits to 12 randomly selected male professional...

A sports researcher gave a standard questionnaire of eating habits to 12 randomly selected male professional athletes, four each from baseball, football, and basketball. The results were:

Baseball: 34, 18, 21, 65

Football: 27, 28, 67, 42

Basketball: 35, 44, 47, 61

Is there a significant difference in eating habits among professionals in the three sports? (Use the .05 sig level.)

Solutions

Expert Solution

H0: μ1 = μ2 = μ3
H1: There is at least one mean difference among the populations.

Applying one way ANOVA:

Baseball Football basketball
34 27 35
18 28 44
21 67 47
65 42 61
count ni= 4 4 4
Average==ΣXi/ni= 34.5000 41.0000 46.7500
Total=ΣX2i   =   6146.000 7766.0000 9091.0000
SS=ΣX2i -(Σxi)2/ni= 1385.000 1042.0000 348.7500
Grand average Xgrand =∑xi/N = 489/8= 40.7500
i ni i ni*(Xi-Xgrand)2 SS=(ni-1)*s2
treatment 1 4 34.5000 156.250 1385
treatment 2 4 41.0000 0.250 1042
treatment 3 4 46.7500 144.000 348.75
Total 12 300.500 2775.7500
SSTr SSE
df treatments = number of treatments-1= 2
df error = N-k= 12-3= 9
df total= N-1= 12-1= 11
MS(treatment) =SSTr/df(Tr)=300.5/2= 150.25000
MS(error) =SSE/df(error)=2775.75/9= 308.41667
test statistic F =MSTr/MSE =150.25/308.42= 0.487

for (2,11) degree of freedom and 0.05 level  critical value =4.26

since test statistic < critical value, we fail to reject null hypothesis

we do not have significant evidence to conclude that  there is a significant difference in eating habits among professionals in the three sports


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