The first five ionization energies of an atom X are 6, 19, 28,120, and 154...

The first five ionization energies of an atom X are 6, 19, 28, 120, and 154 eV. Sugust what 3rd row element X is and give reasons for your choice.

Solutions

Expert Solution

3rd row series contains;

Na Mg Al Si P S Cl Ar

First we will look for the difference in the magnitude of I.E

1st-2nd 2nd-3rd 3rd-4th 4th-5th

13 9 92 34

So as we can see on the above scale is that after removal of 3rd electron, a huge amount of energy is needed to remove the 4th electron from the shell.

Hence, number of valence electron present in the element = 3e

If we carefully look for the electronic configuration for above series, Al = 3s² 3p¹

As removal of an extra electron (basically from 2nd shell) needs a much higher amount of energy compare to 3rd (valence shell).

Our proposed element X is Aluminium

queen_honey_blossom answered 1 year ago

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