The first and second ionization energies of two elements from the 3rd row of the periodic...

The first and second ionization energies of two elements from the 3rd row of the periodic table are given below.

Element A: 738 kJ/mol and 1451 kJ/mol

Element B: 496 kJ/mol and 4562 kJ/mol

What is element B?

Solutions

Expert Solution

second ionisation energy of element B is much higher tha first ionisation energy
so, B after lossing one electron attain nobel gas configuration
also, given element is from third row
so, it must be Na

Answer : Na

queen_honey_blossom answered 1 year ago

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