In: Chemistry
The first and second ionization energies of two elements from the 3rd row of the periodic table are given below.
Element A: 738 kJ/mol and 1451 kJ/mol
Element B: 496 kJ/mol and 4562 kJ/mol
What is element B?
second ionisation energy of element B is much higher tha first
ionisation energy
so, B after lossing one electron attain nobel gas
configuration
also, given element is from third row
so, it must be Na
Answer : Na