The first two ionization energies of an unknown element are as follows: 1st I.E = 496...

The first two ionization energies of an unknown element are as follows: 1st I.E = 496 kJ/mol 2nd I.E = 4560 kJ/mol Predict which group this element belongs to and write down the electron configuration of its valence electrons

Q2. Explain why the first ionization energy of sulfur is inferior to that of phosphorus

Expert Solution

queen_honey_blossom answered 2 years ago

An unknown element has the following ionization energies:

An unknown element has the following ionization energies:Please answer all questionsIE1 = 570 kJ/mol IE2 = 1431 kJ/mol IE3 = 2023 kJ/mol IE4 = 10,521 kJ/mol IE5 = 13,288 kJ/mol a) Based on this information, how many valence electrons does this element have?Explain your answer.b) In view of your answer in part a), what charge would this element likely form, and would it be a metal or non-metal? (Assume it is not a metalloid). Explain.

Table 4.1: Ionization Energies Complete the ionization energies for each element.

Table 4.1: Ionization EnergiesComplete the ionization energies for each element.ElementHHeLiBeBCNOFNeNaMgAlAtomic Number12345678910111213Ioni zationEnergies1st1312237252090080110872nd-52517298175723532856338833743952456214513rd--118151484946204578530160506122691077334th---21007622374757469840893719543105435th----37831944510990110231217713354136306th-----472775326713327151641523816613180207th------6436071330178681999920117217118th-------84078920382307025496256619th--------106434115380289323165310th---------1314321413623545811th----------15907516998812th-----------1893682. Explain how the successive (first, second, third, etc) ionization potentials change in each atom.3. For most atoms, there are one or two huge jumps in the ionization potential. Explain why these occur. In aluminum, explain these huge increases using the valence electrons.4. Explain any trend you observe when looking at only the first ionization energies of each of the 13 elements.

The ionization energies for a hypothetical element are listed below. Based on these ionization energies, identify...

The ionization energies for a hypothetical element are listed below. Based on these ionization energies, identify which group the element would be from on the Periodic Table. IE1 (kJ/mol) IE2 (kJ/mol) IE3 (kJ/mol) IE4 (kJ/mol) IE5 (kJ/mol) IE6 (kJ/mol) 600 1200 7300 9580 12,600 14,640

The successive ionization energies for an unknown element are IE1 = 896 kJ/mol IE2 =1752 kJ/mol...

The successive ionization energies for an unknown element are IE1 = 896 kJ/mol IE2 =1752 kJ/mol IE3 =14,807 kJ/mol IE4 =17,948 kJ/mol To which family in the periodic table does the unknown element most likely belong?

Explain why the successive ionization energies (i.e., IE1, IE2, IE3, etc.) for a given element always increase.

Question 1: a. The first four ionization energies of an element are approximately: 738 kJ mol-1,...

Question 1: a. The first four ionization energies of an element are approximately: 738 kJ mol-1, 1450 kJ mol-1, 7.7 x 103 kJ mol-1, and 1.1 x 104 kJ mol-1. Which family (group) of elements does this element belong? Explain. b. In a photoelectron spectroscopy experiment the kinetic energy of the ejected electron from a potassium atom is found to be 5.34 x 10-19 J using a UV source of wavelength 162 nm. Calculate the ionization energy. i. It is...

A main group element has the following five successive ionization energies: 1st IE: 0.58 MJ mol-1,...

A main group element has the following five successive ionization energies: 1st IE: 0.58 MJ mol-1, 2nd IE: 1.52 MJ mol-1, 3rd IE: 2.75 MJ mol-1, 4th IE: 11.58 MJ mol-1, 5th IE: 14.84 MJ mol-1. Which group contains this element? Why?

An element Y has the ionization energies shown in the table. Element Y is likely_____ a....

An element Y has the ionization energies shown in the table. Element Y is likely_____ a. K b. Br c. Ca d. Si Ionization energy table: first 419 kj/mol, 2nd 3051 kJ/mol, 3rd 4411 kJ/mol Please explain why

The first four ionization energies in kJ/mol of a certain second-row element are 801, 2427, 3660,...

The first four ionization energies in kJ/mol of a certain second-row element are 801, 2427, 3660, and 25,025. What is the likely identity of the element?

1. Predict which element would have the largest difference between the first and second ionization energies...

1. Predict which element would have the largest difference between the first and second ionization energies a) Sodium b) Phosphorus c) silicon d) magnesium 2. Arrange the elements Li, Ne, Ar, and Na in increasing order of the energy required to remove the first electron from their respective atoms a) Na < Li < Ar < Ne b) Na < Li < Ne < Ar c) Li < Na < Ar < Ne d) Ar < Ne < Na <...

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