The equivalent synchronous impedance of a 25kVA, 400V three-phase Y-connected synchronous generator is 0.05 + j1.6...

The equivalent synchronous impedance of a 25kVA, 400V
three-phase Y-connected synchronous generator is 0.05 + j1.6 ohm.
When the rated voltage was output under no load, the rated current flowed by connecting the load.
Part a)
If the load power factor is 0.8, 1.0 lagging, and 0.8 lagging,
calculate the pull-up voltage, load angle, and voltage fluctuation rate for each.
Ignore the magnetic saturation.

Part b)
If the power factor is 0.8, 1.0 lagging and 0.8 leading,
when the rated current flows through the generator at the rated output voltage,
calculate the internal induced power, load angle, and voltage dynamic for each.

Answer
Part a)
190.4V, 11.26 deg, 21.3%
221.8V, 14.47 deg, 4.1%
259.2V, 11.82 deg, -11.3%

Part b)
270.8V, 9.59 deg, 17.5%
239.8V, 13.93 deg, 3.8%
203.3V, 13.45 deg -12.0%

Expert Solution

Manojponduru answered 3 hours ago

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