Question

An industrial psychologist is interested in the effectiveness of an employee computer training course. A total of 12 employees are enrolled in the course. The psychologist measures computer knowledge (1) just before the training begins, (2) again at the end of training, and (3) again at a 3-month follow-up. An increase in computer knowledge from pre-training to end-of-training would suggest the training is effective. Scores on the computer knowledge test can range from 1 to 10. The tables below summarize the data and part of the data analysis:

Source                                    SS                      df                              MS                       F                             p                            eta2

IV                                         20.00                    2                            ____               ______                  _____             _____

Error                                      44.50                     22                           ____                  

Subjects                               42.13                      ___

Total                                      _____                   35                          

a. Describe the statistical test to be done.

b. State the null and alternative hypotheses.

c. What is the critical value of the test statistic? What is the decision rule for rejecting the null hypothesis?

CV:         _________________________          df:___________             Reject H₀ if F ________________

Based on the findings presented in your summary table, did you reject H_o? (Circle or highlight response)

Reject H_o                                                                             Fail to reject H_o

Answer 1

Source	SS	df	MS	F	p	eta2
IV	20	2	10	4.943	.016902	0.1875
Error	44.5	22	2.0227
Subjects	42.13	11
Total	106.63	35

a) The test done above is ANOVA (analysis of variance )

b) Null hypothesis : There is no effect of employment computer training course.

Alternate hypothesis :- there is a effect of employment computer training course that is the overall score before and after training has increased.

c) F critical =3.44 and F calculated =4.943

If the calculated F value is greater than the critical value we reject the null hypothesis.

CV=3.44 df=(2,22) Reject Ho if F >3.44

Based on the calculated value we reject Ho that is we conclude that the training is effective .