In: Chemistry
What is ΔG° at 298 K for the following reaction? HCN( g )+N H 3 ( g )→C H 4 ( g )+ N 2 ( g ) ; ΔH°=−164.1kJ; ΔS°=−17J/K at 298 K?
We know the equation
G0
=
H0
-T
S0
Now from given values
G0 =
-164.1 kJ - 298 K ( -17 x 10-3 kJ/K) ................
make J to kJ for
S0
values
= -164.1 kJ + 5.066 kJ
= -159.034 kJ
So
Answer is
-159.034 kJ