Question

In: Chemistry

What is ΔG° at 298 K for the following reaction? HCN( g )+N H 3 (...

What is ΔG° at 298 K for the following reaction? HCN( g )+N H 3 ( g )→C H 4 ( g )+ N 2 ( g ) ;   ΔH°=−164.1kJ;    ΔS°=−17J/K   at   298 K?

Solutions

Expert Solution

We know the equation

G0 =H0 -TS0  

Now from given values

G0 = -164.1 kJ - 298 K ( -17 x 10-3 kJ/K) ................ make J to kJ for S0 values

= -164.1 kJ + 5.066 kJ

= -159.034 kJ

So

Answer is

-159.034 kJ


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