In: Chemistry
Determine the equilibrium constant for the following reaction at 655 K. HCN(g) + 2 H2(g) → CH3NH2(g) ΔH° = -158 kJ; ΔS°= -219.9 J/K
ΔHo = -158 KJ/mol
ΔSo = -219.9 J/mol.K
= -0.2199 KJ/mol.K
T = 655 K
use:
ΔGo = ΔHo - T*ΔSo
ΔGo = -158.0 - 655.0 * -0.2199
ΔGo = -13.9655 KJ/mol
T = 655 K
ΔGo = -13.9655 KJ/mol
ΔGo = -13965.5 J/mol
use:
ΔGo = -R*T*ln Kc
-13965.5 = - 8.314*655.0* ln(Kc)
ln Kc = 2.5645
Kc = 13
Answer: 13