In: Chemistry
Estimate ΔG°rxn for the following reaction at 407 K. HCN(g) + 2 H2(g) → CH3NH2(g) ΔH°= -158.0 kJ; ΔS°= -219.9 J/K
answer choices
-68.5 kJ
+247 kJ
-247 kJ
+68.5 kJ
+61.9 kJ
Given that
ΔH°= -158.0 kJ
ΔS°= -219.9 J/K = -0.2199 kJ/K
T = 407K
We know tht ΔG° = ΔH° - T ΔS°
= -158.0 kJ - (407 K) (-0.2199 kJ/K)
= -68.5 kJ
Therefore,
ΔG°rxn = -68.5 kJ