Consider the following reaction where Kc = 6.50×10-3 at 298 K 2 NOBr (g)-> 2 NO...

Consider the following reaction where Kc = 6.50×10-3 at 298 K

2 NOBr (g)-> 2 NO (g) + Br2 (g)

A reaction mixture was found to contain 8.52×10-2 moles of NOBr (g), 2.31×10-2 moles of NO (g), and 4.58×10-2 moles of Br2 (g), in a 1.00 liter container. Indicate True (T) or False (F) for each of the following:

1. In order to reach equilibrium NOBr(g) must be consumed . 2. In order to reach equilibrium Kc must increase . 3. In order to reach equilibrium NO must be consumed . 4. Qc is greater than Kc. 5. The reaction is at equilibrium. No further reaction will occur.

Solutions

Expert Solution

4. Qc = 3.367*10^-3 , Qc<Kc Ans: statement is 'False'

5. At equilibruim no net reaction takes place but further reaction takes place in both forward and backward direction. Ans: statement is 'False".

queen_honey_blossom answered 1 year ago

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