A three-phase line has an impedance of 1 + j2 Ω per phase. The line feeds...

A three-phase line has an impedance of 1 + j2 Ω per phase. The line feeds two balanced three-phase loads that are connected in parallel. The first load is Y-connected and has an impedance of 20+j40 Ω per phase. The second load is ∆-connected and has an impedance of 30-j60 Ω per phase. The line-to-line voltage at the load end of the line is 415V. Taking the phase voltage Va as reference, determine: a) The total current per phase from the source end .b) The magnitude of the line voltage at the source end of the line c) The total 3-phase real and reactive powers absorbed by each load . d) The total 3-phase real and reactive power losses in the line. e) The real power and reactive power supplied at the source end of the line. f) If the second load is now connected in Y-connection with the same impedance of 30-j60 Ω per phase, what would be the current per phase supplied by the source

Expert Solution

ANSWERS:

(a) I_source=8.63665425<33.56912 amps

(b)(V_source)_Line=412.1892307 volts

(c)P₁=1722.25136 watt,Q₁=3444.499 Var,P₂=3444.499 watts,Q₂=68888.999356 Var

(d)P_Loss=223.77538 watt,Q_Loss=447.5507798 Var

(e)P_Source=5395.502823 watt

Q_Source=2984.6238 Var

(f) (I_Source)2=11.8680<42.1870 amps

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Manojponduru answered 1 year ago

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