In: Physics
An ideal gas has the volume V0. If the temperature and the pressure are each tripled during a process, the new volume is
(a) Vo
(b) 9V0-
(c) 3V0-
(d) 0.33Vo
The option (a) is correct option.
Explanation:
The ideal gas equation is
P1V1/T1 = P2V2/T2
Given that V1 = V0, P2 = 3P1, T2 = 3T1
So, putting these values in above expresion we get;
V2 = P1V0(3T1)/T1(3P1)
= V0
Result:
The volume is unaltered.
Hence, option (a) is correct.
Option (a) is correct.