A gas sample has a temperature of 20. ∘C with an unknown volume. The same gas...

A gas sample has a temperature of 20. ∘C with an unknown volume. The same gas has a volume of 449 mL when the temperature is 89 ∘C, with no change in the pressure and amount of gas. Part A What was the initial volume, in milliliters, of the gas? Express your answer using three significant figures.

Expert Solution

Initial Final

T1 = 20+273 = 293K T2 = 89+273 = 362K

V1 = V2 = 449ml

V1/T1 = V2/T2

V1 = V2T1/T2

= 449*293/362

= 363ml

The initial volume = 363ml >>>>answer

queen_honey_blossom answered 2 years ago

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