If 4.71 moles of an ideal gas has a pressure of 3.55 atm, and a volume...

If 4.71 moles of an ideal gas has a pressure of 3.55 atm, and a volume of 26.09 L, what is the temperature of the sample in degrees Celsius?

Expert Solution

Ans. Using ideal gas equation-

PV = nRT - equation 1

Where, P = pressure in atm

V = volume in L

n = number of moles

R = universal gas constant= 0.0821 atm L mol^-1K^-1

Putting the values in equation 1-

3.55 atm x 26.09 L = 4.71 mol x (0.0821 atm L mol^-1K^-1) x T

Or, T = 92.61650 atm L / (0.386691 atm L K^-1)

Hence, T = 239.52 K

Hence, temperature, T = (239.52 – 273.15)⁰C = -33.63⁰C

queen_honey_blossom answered 2 years ago

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